Integrand size = 26, antiderivative size = 65 \[ \int \frac {\tan ^5(e+f x)}{\sqrt {a-a \sin ^2(e+f x)}} \, dx=\frac {a^2}{5 f \left (a \cos ^2(e+f x)\right )^{5/2}}-\frac {2 a}{3 f \left (a \cos ^2(e+f x)\right )^{3/2}}+\frac {1}{f \sqrt {a \cos ^2(e+f x)}} \]
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Time = 0.15 (sec) , antiderivative size = 65, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {3255, 3284, 16, 45} \[ \int \frac {\tan ^5(e+f x)}{\sqrt {a-a \sin ^2(e+f x)}} \, dx=\frac {a^2}{5 f \left (a \cos ^2(e+f x)\right )^{5/2}}-\frac {2 a}{3 f \left (a \cos ^2(e+f x)\right )^{3/2}}+\frac {1}{f \sqrt {a \cos ^2(e+f x)}} \]
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Rule 16
Rule 45
Rule 3255
Rule 3284
Rubi steps \begin{align*} \text {integral}& = \int \frac {\tan ^5(e+f x)}{\sqrt {a \cos ^2(e+f x)}} \, dx \\ & = -\frac {\text {Subst}\left (\int \frac {(1-x)^2}{x^3 \sqrt {a x}} \, dx,x,\cos ^2(e+f x)\right )}{2 f} \\ & = -\frac {a^3 \text {Subst}\left (\int \frac {(1-x)^2}{(a x)^{7/2}} \, dx,x,\cos ^2(e+f x)\right )}{2 f} \\ & = -\frac {a^3 \text {Subst}\left (\int \left (\frac {1}{(a x)^{7/2}}-\frac {2}{a (a x)^{5/2}}+\frac {1}{a^2 (a x)^{3/2}}\right ) \, dx,x,\cos ^2(e+f x)\right )}{2 f} \\ & = \frac {a^2}{5 f \left (a \cos ^2(e+f x)\right )^{5/2}}-\frac {2 a}{3 f \left (a \cos ^2(e+f x)\right )^{3/2}}+\frac {1}{f \sqrt {a \cos ^2(e+f x)}} \\ \end{align*}
Time = 0.18 (sec) , antiderivative size = 43, normalized size of antiderivative = 0.66 \[ \int \frac {\tan ^5(e+f x)}{\sqrt {a-a \sin ^2(e+f x)}} \, dx=\frac {15-10 \sec ^2(e+f x)+3 \sec ^4(e+f x)}{15 f \sqrt {a \cos ^2(e+f x)}} \]
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Time = 0.64 (sec) , antiderivative size = 48, normalized size of antiderivative = 0.74
method | result | size |
default | \(\frac {15 \left (\cos ^{4}\left (f x +e \right )\right )-10 \left (\cos ^{2}\left (f x +e \right )\right )+3}{15 \cos \left (f x +e \right )^{4} \sqrt {a \left (\cos ^{2}\left (f x +e \right )\right )}\, f}\) | \(48\) |
risch | \(\frac {2 \,{\mathrm e}^{8 i \left (f x +e \right )}+\frac {8 \,{\mathrm e}^{6 i \left (f x +e \right )}}{3}+\frac {116 \,{\mathrm e}^{4 i \left (f x +e \right )}}{15}+\frac {8 \,{\mathrm e}^{2 i \left (f x +e \right )}}{3}+2}{\sqrt {\left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right )^{2} a \,{\mathrm e}^{-2 i \left (f x +e \right )}}\, \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right )^{4} f}\) | \(91\) |
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Time = 0.29 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.77 \[ \int \frac {\tan ^5(e+f x)}{\sqrt {a-a \sin ^2(e+f x)}} \, dx=\frac {{\left (15 \, \cos \left (f x + e\right )^{4} - 10 \, \cos \left (f x + e\right )^{2} + 3\right )} \sqrt {a \cos \left (f x + e\right )^{2}}}{15 \, a f \cos \left (f x + e\right )^{6}} \]
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\[ \int \frac {\tan ^5(e+f x)}{\sqrt {a-a \sin ^2(e+f x)}} \, dx=\int \frac {\tan ^{5}{\left (e + f x \right )}}{\sqrt {- a \left (\sin {\left (e + f x \right )} - 1\right ) \left (\sin {\left (e + f x \right )} + 1\right )}}\, dx \]
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Time = 0.21 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.06 \[ \int \frac {\tan ^5(e+f x)}{\sqrt {a-a \sin ^2(e+f x)}} \, dx=\frac {15 \, {\left (a \sin \left (f x + e\right )^{2} - a\right )}^{2} a^{3} + 10 \, {\left (a \sin \left (f x + e\right )^{2} - a\right )} a^{4} + 3 \, a^{5}}{15 \, {\left (-a \sin \left (f x + e\right )^{2} + a\right )}^{\frac {5}{2}} a^{3} f} \]
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Time = 1.66 (sec) , antiderivative size = 67, normalized size of antiderivative = 1.03 \[ \int \frac {\tan ^5(e+f x)}{\sqrt {a-a \sin ^2(e+f x)}} \, dx=\frac {16 \, {\left (10 \, \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{4} - 5 \, \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 1\right )}}{15 \, {\left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 1\right )}^{5} \sqrt {a} f \mathrm {sgn}\left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{4} - 1\right )} \]
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Time = 21.86 (sec) , antiderivative size = 486, normalized size of antiderivative = 7.48 \[ \int \frac {\tan ^5(e+f x)}{\sqrt {a-a \sin ^2(e+f x)}} \, dx=\frac {4\,{\mathrm {e}}^{e\,3{}\mathrm {i}+f\,x\,3{}\mathrm {i}}\,\sqrt {a-a\,{\left (\frac {{\mathrm {e}}^{-e\,1{}\mathrm {i}-f\,x\,1{}\mathrm {i}}\,1{}\mathrm {i}}{2}-\frac {{\mathrm {e}}^{e\,1{}\mathrm {i}+f\,x\,1{}\mathrm {i}}\,1{}\mathrm {i}}{2}\right )}^2}}{a\,f\,\left ({\mathrm {e}}^{e\,2{}\mathrm {i}+f\,x\,2{}\mathrm {i}}+1\right )\,\left ({\mathrm {e}}^{e\,1{}\mathrm {i}+f\,x\,1{}\mathrm {i}}+{\mathrm {e}}^{e\,3{}\mathrm {i}+f\,x\,3{}\mathrm {i}}\right )}-\frac {32\,{\mathrm {e}}^{e\,3{}\mathrm {i}+f\,x\,3{}\mathrm {i}}\,\sqrt {a-a\,{\left (\frac {{\mathrm {e}}^{-e\,1{}\mathrm {i}-f\,x\,1{}\mathrm {i}}\,1{}\mathrm {i}}{2}-\frac {{\mathrm {e}}^{e\,1{}\mathrm {i}+f\,x\,1{}\mathrm {i}}\,1{}\mathrm {i}}{2}\right )}^2}}{3\,a\,f\,{\left ({\mathrm {e}}^{e\,2{}\mathrm {i}+f\,x\,2{}\mathrm {i}}+1\right )}^2\,\left ({\mathrm {e}}^{e\,1{}\mathrm {i}+f\,x\,1{}\mathrm {i}}+{\mathrm {e}}^{e\,3{}\mathrm {i}+f\,x\,3{}\mathrm {i}}\right )}+\frac {352\,{\mathrm {e}}^{e\,3{}\mathrm {i}+f\,x\,3{}\mathrm {i}}\,\sqrt {a-a\,{\left (\frac {{\mathrm {e}}^{-e\,1{}\mathrm {i}-f\,x\,1{}\mathrm {i}}\,1{}\mathrm {i}}{2}-\frac {{\mathrm {e}}^{e\,1{}\mathrm {i}+f\,x\,1{}\mathrm {i}}\,1{}\mathrm {i}}{2}\right )}^2}}{15\,a\,f\,{\left ({\mathrm {e}}^{e\,2{}\mathrm {i}+f\,x\,2{}\mathrm {i}}+1\right )}^3\,\left ({\mathrm {e}}^{e\,1{}\mathrm {i}+f\,x\,1{}\mathrm {i}}+{\mathrm {e}}^{e\,3{}\mathrm {i}+f\,x\,3{}\mathrm {i}}\right )}-\frac {128\,{\mathrm {e}}^{e\,3{}\mathrm {i}+f\,x\,3{}\mathrm {i}}\,\sqrt {a-a\,{\left (\frac {{\mathrm {e}}^{-e\,1{}\mathrm {i}-f\,x\,1{}\mathrm {i}}\,1{}\mathrm {i}}{2}-\frac {{\mathrm {e}}^{e\,1{}\mathrm {i}+f\,x\,1{}\mathrm {i}}\,1{}\mathrm {i}}{2}\right )}^2}}{5\,a\,f\,{\left ({\mathrm {e}}^{e\,2{}\mathrm {i}+f\,x\,2{}\mathrm {i}}+1\right )}^4\,\left ({\mathrm {e}}^{e\,1{}\mathrm {i}+f\,x\,1{}\mathrm {i}}+{\mathrm {e}}^{e\,3{}\mathrm {i}+f\,x\,3{}\mathrm {i}}\right )}+\frac {64\,{\mathrm {e}}^{e\,3{}\mathrm {i}+f\,x\,3{}\mathrm {i}}\,\sqrt {a-a\,{\left (\frac {{\mathrm {e}}^{-e\,1{}\mathrm {i}-f\,x\,1{}\mathrm {i}}\,1{}\mathrm {i}}{2}-\frac {{\mathrm {e}}^{e\,1{}\mathrm {i}+f\,x\,1{}\mathrm {i}}\,1{}\mathrm {i}}{2}\right )}^2}}{5\,a\,f\,{\left ({\mathrm {e}}^{e\,2{}\mathrm {i}+f\,x\,2{}\mathrm {i}}+1\right )}^5\,\left ({\mathrm {e}}^{e\,1{}\mathrm {i}+f\,x\,1{}\mathrm {i}}+{\mathrm {e}}^{e\,3{}\mathrm {i}+f\,x\,3{}\mathrm {i}}\right )} \]
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